Types of errors, determined when checking the location of subobjects

1

The subobject contour intersects with the main contour: the subobject point (a) lies on line segment AB. The belonging of a point to a segment is determined by the condition: the distance between the point and the segment is less than the threshold for removing the identical metric points (usually 0.001 mm).

Method of correction: if the change of the object's area is acceptable, increase the distance between the point and the segment (move the subobject point by 0.5 mm to the left).

2

The subobject contour intersects with the main contour: the segments of the subobject (ac, ba) intersect the segment AB.

Method of correction: move the subobject point inside the main contour; if necessary, digitize an additional object to the right of the line segment AB.

3

The subobject contour is outside the main contour.

Method of correction: digitize additional object along the contour of the subobject (abc), then delete the subobject.

4

The subobject contour is located outside the main contour and adjoins the main contour at point A (a).

Method of correction: digitize additional object along the contour of the subobject (abc), then delete the subobject.

5

The subobject contour is located outside the main contour and adjoins the main contour: the contours have a common segment AB (ac).

Method of correction: digitize the object along the contour of the subobject (abc), then delete the subobject.

6

The subobject contour is located inside the main contour and adjoins the main contour at point A (a).

Method of correction: if the change of the object's area is acceptable, increase the distance between points (move point A by 0.5 mm to the right).

7

The subobject contour is located inside the main contour and adjoins the main contour: the contours have a common segment AB (ac).

Method of correction: digitize the object along the AbBCD contour, then delete the original object.

8

The contour of the subobject coincides with the main contour. The areas of the subobjects are subtracted from the area of the main contour, so the area of such an object is 0.

Method of correction: delete a subobject (abc) or delete an object.

9

The contour of the subobject is outside the main contour. The areas of the subobjects are subtracted from the area of the main contour, so the area of such an object is negative.

Method of correction: digitize the object along the contour of the subobject (abcd) and the subobject along the contour ABC, then delete the original object.